Question

PLEASE HELP!!
The unknown concentration of NaOH was determined by titration with HCl. The following data was collected: mL NaOH = 34.8 mL mL of HCl used = 29.6 mL concentration of HCl = 0.19 M What is the concentration of the NaOH? 0.16 M 0.22 M 4.5 M 6.3 M

Answer 1

Answer:

0.16 M

Explanation:

We are given;

• Volume of NaOH as 34.8 mL
• Volume of HCl as 29.6 mL
• Molarity of HCl is 0.19 M

We are required to determine the concentration of the NaOH

We are going to write the equation of the reaction first;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

We can then determine the number of moles HCl

Moles = Molarity × volume

          = 0.19 M × 0.0296 L

          = 0.005624 moles

We the determine the number of moles of NaOH

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = moles of HCl

                     = 0.005624 moles

Finally, we determine the concentration of NaOH

Concentration/Molarity = Number of moles ÷ Volume

                                      = 0.005624 moles ÷ 0.0348 L

                                      = 0.1616 M

                                      = 0.16 M

Answer 2

Answer:

0.16

Explanation: