Question

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2axv2=v02+2ax. The problem requires solving for x, and the known values for the system are: a = 2.55meter/second, v0 = 21.8meter/second, and v = 0meter/second. Perform the next step in the analysis.

Answer 1

Answer:

x = -93.2meters

Step-by-step explanation:

$v^{2}=v_{0} ^{2} + 2ax$

Make x the subject of the formula;

$v^{2}-v_{0} ^{2}=2ax$

Divide both sides by 2a

$\frac{v^{2}-v_{0} ^{2}}{2a}=\frac{2ax}{2a} \\\\\frac{v^{2}-v_{0} ^{2}}{2a}=x\\\\x = \frac{v^{2}-v_{0} ^{2}}{2a}$

Subsituting the values for v, v0, and a, we have

$x=\frac{0^{2}-(21.8)^{2}}{2*2.55}\\ \\x= \frac{0-475.24}{5.1}=\frac{-475.24}{5.1}\\ \\x = -93.1843$

x ≅ -93.2meters