Question

A sample of neon initially has a volume of 2.50 L at 15 degrees Celsius. What is final temperature, in degrees Celsius, is needed to change the volume of the gas to 1.25 L?

Answer 1

Answer:

—129°C

Explanation:

First, we analyze what was given from the question as follows:

V1 = 2.50L

T1 = 15°C = 15 +273 = 288K

V2 = 1.25L

T2 =?

V1 / T1 = V2 /T2

2.5/288 = 1.25/T2

Cross multiply to express in linear form

2.5 x T2 = 288 x 1.25

Divide both side by the coefficient of T2 i.e 2.5

T2 = (288 x 1.25) / 2.5

T2 = 144K

Converting this temperature(144K) to degree Celsius, we have

T°C = K — 273

T°C = 144 — 273

T°C = —129°C

Answer 2

The final temperature, in degrees Celsius, is mathematically given as

TC = —129°C

What is the final temperature, in degrees Celsius, is needed to change the volume of the gas to 1.25 L?

Question Parameters:

a sample of neon initially has a volume of 2.50 L at 15 degrees Celsius

Generally, the equation for the  ideal gas is mathematically given as

V1 / T1 = V2 /T2

Therefore

2.5/288 = 1.25/T2

T2 = 144K

In conclusion, temperature, in degrees Celsius

TC = K — 273

TC = 144 — 273

TC = —129°C

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