Answer:
a) Mean = 1
b) Variance = 0.9
Step-by-step explanation:
We are given the following in the question:
P(Success of exploration) = 0.1
Then the number of adults follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
All the explorations are independent.
where n is the total number of observations, x is the number of success, p is the probability of success.
Here n = 10, p = 0.1
a) Mean number of successful explorations
[tex]\mu = np = 10(0.1) = 1[/tex]
b) Variance number of successful explorations
[tex]\sigma^2 = np(1-p) = (10)(0.1)(1-0.1) = 0.9[/tex]