An oil exploration firm is formed with enough capital to perform ten explorations. The probability of a particular exploration being successful is 0.1. Assume that the explorations are independent. Find the mean and variance of the number of successful explorations.

Respuesta :

Answer:

a) Mean = 1

b) Variance = 0.9      

Step-by-step explanation:

We are given the following in the question:

P(Success of exploration) = 0.1

Then the number of adults follows a binomial distribution, where

[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]

All the explorations are independent.

where n is the total number of observations, x is the number of success, p is the probability of success.

Here n = 10, p = 0.1

a) Mean number of successful explorations

[tex]\mu = np = 10(0.1) = 1[/tex]

b) Variance number of successful explorations

[tex]\sigma^2 = np(1-p) = (10)(0.1)(1-0.1) = 0.9[/tex]

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