Answer:
number of pulses produced = 162 pulses
Explanation:
give data
radius = 50 mm
encoder produces = 256 pulses per revolution
linear displacement = 200 mm
solution
first we consider here roll shaft encoder on the flat surface without any slipping
we get here now circumference that is
circumference = 2 π r .........1
circumference = 2 × π × 50
circumference = 314.16 mm
so now we get number of pulses produced
number of pulses produced = [tex]\frac{linear\ displacement}{circumference}[/tex] × No of pulses per revolution .................2
number of pulses produced = [tex]\frac{200}{314.16}[/tex] × 256
number of pulses produced = 162 pulses