Question

a line passed through the point (8,9) and has a slope of -3/4. write an equation in slope intercept form.

Answer 1

Answer:

y = -3/4x + 3

Step-by-step explanation:

y - 9 = -3/4 (x-8)

y-9 = -3/4x -6

y = -3/4x - 6 + 9

y = -3/4x + 3

Answer 2

The equation of the line that passed through the point (8,9) and has a slope of -3/4 in slope-intercept form is $y= -\frac{3}{4}x + 13$

The point-slope form of the equation of a line passing through the points (x₁, y₁) and with a slope m is given as:

y - y₁ = m(x - x₁)

For the line that passed through the point (8, 9) and has a slope of -3/4

x₁ = 8, y₁ = 9, and m = -3/4

Substitute these values into the equation y - y₁ = m(x - x₁)

$y-9=\frac{-3}{4}(x - x_1)$

Express the equation above in the form y = mx + c

$y-9=-\frac{3}{4}(x - 8)\\\\y-9= -\frac{3}{4}x + 6\\\\y= -\frac{3}{4}x + 6+9\\\\y= -\frac{3}{4}x + 13$

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