Find the perimeter of the following shape, rounded to the nearest tenth:
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Answer: the perimeter of the shape is 19.1
Step-by-step explanation:
To determine the length of each side of the quadrilateral, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side
For line AD,
AD² = 2² + 4² = 4 + 16 = 20
AD = √20 = 4.47
For line AB,
AB² = 1² + 5² = 1 + 25 = 26
AB = √26 = 5.1
For line BC,
BC² = 2² + 4² = 4 + 16 = 20
BC = √20 = 4.47
For line CD,
CD² = 1² + 5² = 1 + 25 = 26
CD = √26 = 5.1
The perimeter of a plane figure is the distance around the figure. Therefore
Perimeter = AB + AB + BC + CD
Perimeter = 4.47 + 5.1 + 4.47 + 5.1 =
19.1