Answer:
[tex]l=7.853\ cm\approx0.079\ m[/tex]
Explanation:
Given:
As we know, resistance:
[tex]R=\rho \frac{l}{a}[/tex]
[tex]1=1.6\times 10^{-8}\times \frac{l}{\pi.\frac{d^2}{4} }[/tex]
[tex]\frac{1}{1.6} \times 10^8\times \pi\times \frac{(4\times 10^{-5})^2}{4} =l[/tex]
[tex]l=7.853\ cm\approx0.079\ m[/tex]