Answer:
He can take 5 shirt of 56 different group.
Step-by-step explanation:
Given, Christopher is packing his bags for his vacation. He has 8 unique shirts , but only 5 fit in his bag.
[tex]^8C_5=\frac{ {8!}}{5!(8-5)!} =\frac{8!}{5!3!} =56[/tex]
He can take 5 shirt of 56 different group.