Answer:
A. Write the rate law for this reaction
2A + B -----> C
Rate law is expressed as
-rA = kaCa^αCb^β
n = α + β
Where, ka is the rate constant;
Ca is the concentration of reactant A, Cb is the conversation of reactant B, α is the rate order for reactant A, β is the rate order for reactant B, n is the overall order.
1. β = 2, n = 3; α = 3-2 = 1
Rate law is;
-rA = ka[A][B]^2
2. α = 0, β = 1
-rA = ka[A]^0[B]
-rA = ka[B]
3. α=β=0
-rA = ka[A]^0[B]^0
-rA = ka
4. α=1, n = 0
The reaction is zero order as it is independent of the reactants.
-rA = ka
B. Rate law for the following;
a. H2+ Br2 ------>2HBr
-rA1 = ka[H2] . [Br2]
-rA2 = kb[HBr]^2
Comparing both rate, rA1= rA2
ka.[H2][Br2] = kb[HBr]^2
ka/kb = K = [HBr]^2 / [H2] [Br2]
b. H2 + I2 ------>2HI
K = [HI]^2 / [H2] [I2]