Question

What is the concentration of K+K+ in 0.15 MM of K2SK2S? Express your answer to one decimal place and include the appropriate units.

Answer 1

Answer : The concentration of $K^+$ ion in 0.15 M $K_2S$ is, 0.3 M

Explanation :

The given compound is, $K_2S$

When $K_2S$ dissociates then it gives potassium ion and sulfide ion.

The balanced dissociation reaction is:

$K_2S\rightarrow 2K^++S^{2-}$

By the stoichiometry we can say that, 1 mole of $K_2S$ dissociates to give 2 moles of $K^+$ ion and 1 mole of $S^{2-}$ ion.

Or, in terms of concentration we can say that:

0.15 M of $K_2S$ dissociates to give $2\times 0.15M=0.3M$ of $K^+$ ion and 0.15 M of $S^{2-}$ ion.

Thus, the concentration of $K^+$ ion in 0.15 M $K_2S$ is, 0.3 M