The planes are 618.75 miles from starting point
Solution:
Let t is the travel time of the jet
Then (t + 3) is the travel time of the propellar
When the jet overtakes the propellar, they will traveled the same distance
Distance is given as:
[tex]Distance = speed \times time[/tex]
A jet plane traveling at 550 mph
[tex]Distance\ by\ jet = 550 \times t\\\\Distance\ by\ jet = 550t[/tex]
propeller plane traveling at 150 mph
[tex]Distance\ by\ propellar = 150 \times (t+3)[/tex]
Equate both distance
[tex]550t = 150(t+3)\\\\550t = 150t + 450\\\\550t - 150t = 450\\\\400t = 450\\\\t = \frac{450}{400}\\\\t = 1.125[/tex]
[tex]Distance = 550 \times t = 550 \times 1.125\\\\Distance = 618.75[/tex]
Thus they are 618.75 miles from starting point