Question

When 9.36 g sodium hydroxide is dissolved in enough water to make a total volume of 965 mL, what is the concentration of the resulting solution?

Answer 1

Answer:

0.2425 M

Explanation:

Given mass = 9.36 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{9.36\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 0.234\ mol$

Given that:- Volume = 965 mL = 0.965 L ( 1 mL = 0.001 L )

So,

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.234\ mol}{0.965\ L}=0.2425\ M$

Answer 2

Answer:

The concentration of the solution is 0.242 M

Explanation:

Step 1: Data given

Mass NaOH = 9.36 grams

Volume water = 965 mL = 0.965 L

Molar mass NaOH = 40 g/mol

Step 2: Calculate moles NaOH

Moles NaOH = mass NaOH / molar mass NaOH

Moles NaOH = 9.36 grams / 40.0 g/mol

Moles NaOH = 0.234 moles

Step 3: Calculate concentration

Concentration = moles / volume

Concentration = 0.234 moles / 0.965 L

Concentration = 0.242 M

The concentration of the solution is 0.242 M