Question

Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt.

Answer 1

Answer:

The molality is 0.930 mol/kg

Explanation:

Molality = molarity ÷ density

Molarity of sucrose = 1.06 M = 1.06 mol/L

Density of sucrose = 1.14 g/mL = 1.14 g/mL × 1 kg/1000 g × 1 mL/ 0.001 L = 1.14 kg/L

Molality = 1.06 mol/L ÷ 1.14 kg/L = 0.930 mol/kg