Answer:
a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
[tex] X \sim Unif(a=0,b=8)[/tex]
Where a and b represent the limits of the distribution.
b) [tex] f(x) = \frac{1}{8}= 0.125, a\leq x \leq b[/tex]
And the height for this case would be 0.125
Step-by-step explanation:
Part a
For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
[tex] X \sim Unif(a=0,b=8)[/tex]
Where a and b represent the limits of the distribution.
Part b
For this case the density function would be given by:
[tex] f(x) = \frac{1}{8}= 0.125, a\leq x \leq b[/tex]
And the height for this case would be 0.125
And [tex] f(x)= 0[/tex] for other case.
The cumulative distribution function would be given by:
[tex] F(x) = 0, x<0[/tex]
[tex] F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8[/tex]
[tex] F(x) = 1, x\geq 8[/tex]