Question

The length and width of a living room is 5.5 m and 4.8 m with an uncertainty of 0.1 m in each measurement. The perimeter of the room with associated uncertainty using either the "general method" or the "high/low method" presented in the pre-lab notes is:

(A) 20.6 + 0.2 m
(B) 20.6 0.1 m
(C) 20.6 + 0.6 m
(D) 20.6+ 0.4 m
(E) 20.6t0.8 m

Answer 1

Answer:

The perimeter of room is $(20.6 \pm 0.4)~m$

Step-by-step explanation:

We are given the following in the question:

The length and width of a room are measured with uncertainties.

There is  uncertainty of 0.1 m in each measurement.

Length = $(5.5 \pm 0.1)~m$

Width = $(4.8 \pm 0.1)~m$

Formula:

The perimeter of room is given by:

$P = 2\times (\text{Length + Width})\\P = 2\times ((5.5\pm 0.1)+ (4.8\pm 0.1))\\= 2\times (10.3\pm 0.2)\\P = (20.6 \pm 0.4)~m$

The uncertainties are also added and multiplied.

Thus,the perimeter of room is $(20.6 \pm 0.4)~m$