In Fig. 23-45, a small circular hole of radius R = 1.80 cm has been cut in the middle of an infinite, flat, nonconducting surface that has uniform charge density σ = 4.50 pC/m2 . A z axis, with its origin at the hole’s center, is perpendicular to the surface. In unitvector notation, what is the electric field at point P at z = 2.56 cm?

Respuesta :

Answer:

The electric field at point a =( 0.232N/c)k

Explanation:

E = E1+E2=(6/2Eo)K+(-6/2Eo)[1-(2/(sqrtz^2+R^2)k

E= 6z/2Eo(sqrtz^2+R^2)k

E= (4.5×10^-12)×(2.56×10^-2) /2(8.85×10^-12)sqrt(2.56×10^-2)^2+(1.30×10^-2)^2k

E= 1.152×10^-13/(1.77×10^-11)×(2.8×10^-2)k

E= 1.152×10^-13/(4.956×10^-13)k

E=( 0.232N/c)K

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