Answer:0.0156
Explanation:
If the test cross is between one heterozygous (Aa) and one homologous recessive gene (aa). The possible genotype for their offspring will be
Aa aa Aa aa
The probability of dominant gene (Aa) is 2/4
The probability of recessive gene (aa) is 2/4
The probability that in six offspring 4 is dominant and two recessive is
= 2/4*2/4*2/4*2/4*2/4*2/4
=64/4096
=0.015625
=0.0156 to 4 decimal places
