Answer:
6.38 V
Explanation:
Note: Since the capacitors are identical, The same Charge flows through them.
For the first capacitor,
The Energy stored in a capacitor is given as
E = 1/2qv ............... Equation 1
Where E = Energy stored by the capacitor, q = charge in the capacitor v = Voltage.
make q the subject of the equation
q = 2E/v ................ Equation 2
Given: E = 8 J, v = 51 v.
Substitute into equation 2
q = 8/51
q = 0.3137 C.
For the second capacitor,
v = 2E/q ................... Equation 3
Given: q = 0.3137 C, E = 2 J.
Substitute into equation 3
v = 2/0.3137
v = 6.38 V
Hence the voltage across the second capacitor = 6.38 V
