Question

The sum of the diameters of the largest and smallest pizzas sold at a pizza shop is 25 inches. The difference in their diameters is 15 inches. Find the diameters of the largest and smallest pizzas.

Answer 1

Answer:

20 inches and 5 inches

Step-by-step explanation:

Let the diameter of the largest and the smallest pizza be Y and X respectively.

Then,

Y+X = 25 ........................... Equation 1

Y-X = 15 ............................ Equation 2

Solve equation 1 and equation 2 simultaneously.

Add equation 1 and equation 2

Y+Y = +X+(-X)+25+15

2Y = 40

Y = 40/2

Y = 20 inches.

Also,

Substitute the value of Y into equation 1

20+X=25

X = 25-20

X = 5 inches.

Hence the diameter of the largest and the smallest pizzas = 20 inches and 5 inches

Answer 2

Using a system of equations, it is found that:

• The diameter of the largest pizza is of 20 inches.
• The diameter of the smallest pizza is of 5 inches.

For our system, the diameters are going to be called x and y.

The sum is of 25 inches, hence:

$x + y = 25 \rightarrow y = 25 - x$

The difference is of 15 inches, hence:

$x - y = 15$

Since $y = 25 - x$

$x - (25 - x) = 15$

$2x - 25 = 15$

$2x = 40$

$x = \frac{40}{2}$

$x = 20$

And:

$y = 25 - x = 25 - 20 = 5$

Thus:

• The diameter of the largest pizza is of 20 inches.
• The diameter of the smallest pizza is of 5 inches.

A similar problem is given at https://brainly.com/question/19314231