Question

JKL is a right triangle. JL = 10, KL = 8,
and JK = 6. What is cos L?
10

What is the answer

Answer 1

Answer:

$\cos L = \dfrac{4}{5}$

Step-by-step explanation:

The right angle is angle K. KL and JK are legs. JL is the hypotenuse.

For angle L, KL is the adjacent leg.

In general, for acute angle A of a right triangle,

$\cos A = \dfrac{adjacent~leg}{hypotenuse}$

In this case,

$\cos L = \dfrac{adj~leg}{hyp}$

$\cos L = \dfrac{KL}{JL}$

$\cos L = \dfrac{8}{10}$

$\cos L = \dfrac{4}{5}$