Rate of change of the function: 60
Step-by-step explanation:
The exponential function in this problem is
[tex]f(x)=2^{x+3}[/tex]
The rate of change of a function between a certain interval [tex]x_1 \leq x \leq x_2[/tex] is given by
[tex]r=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]
where
[tex]f(x_1)[/tex] is the value of the function calculated in [tex]x_1[/tex]
[tex]f(x_2)[/tex] is the value of the function calculated in [tex]x_2[/tex]
In this problem, the interval is
[tex]1\leq x \leq 5[/tex]
So we have:
[tex]f(x_1)=f(1)=2^{1+3}=2^4=16[/tex]
and
[tex]f(x_2)=f(5)=2^{5+3}=256[/tex]
Therefore, the rate of change is:
[tex]r=\frac{256-16}{5-1}=60[/tex]
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