A mixture of sand (SiO2), sodium chloride (NaCl), and iron (Fe) filings had a mass of 30.126 g. After analysis this mixture was found to contain 15.976 g of sand and 3.455 g of iron. What is the mass percent (%) of sodium chloride in the sample?

Respuesta :

Answer:

35.5 % NaCl

Explanation:

Total mass of mixture = 30.126 g

Mass of sand = 15.976 g

Mass of iron = 3.455 g

Mass of NaCl = ? → Total mass - 15.976 g - 3.455 g = 10.695 g

% mass of NaCl in the sample → (Mass of NaCl / Total mass) . 100

(10.695 g / 30.126 g) . 100 = 35.5 %