You analyze a sample of unknown metal as you would in this experiment. You measure the volume of H2(g) generated to be 71.85 mL and the water temperature to be 20.0°C. You calculate PH2 to be 0.781 atm. Use the ideal gas law to calculate the number of moles of hydrogen gas generated.

Respuesta :

Answer: The number of moles of hydrogen gas generated is [tex]2.33\times 10^{-3}mol[/tex]

Explanation:

To calculate the number of moles of hydrogen gas, we use the equation given by ideal gas which follows:

[tex]PV=nRT[/tex]

where,

P = pressure of the gas = 0.781 atm

V = Volume of the gas = 71.85 mL = 0.07185 L     (Conversion factor:  1 L = 1000 mL)

T = Temperature of the gas = [tex]20^oC=[20+273]K=293K[/tex]

R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

[tex]0.781atm\times 0.07185L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 293K\\\\n=\frac{0.781\times 0.07185}{0.0821\times 293}=2.33\times 10^{-3}mol[/tex]

Hence, the number of moles of hydrogen gas generated is [tex]2.33\times 10^{-3}mol[/tex]

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