Respuesta :
Answer:
13.19
Explanation:
pH + pOH = 14
pOH = 14 – pH
= 14 – 13.51
= 0.49
[tex][OH]=10^{-pOH}\\=10^{0.49}= 0.323 M[/tex]
When water is added to the solution, then the concentration of the solution is changed.
[tex]M_1V_1=M_2V_2[/tex]
Initial volume is 100 mL
Final volume = 100 + 10 = 110 mL
0.323 M ×100 mL = M2 × 110
[tex]M_2 = \frac{0.323\ M ×100\ mL }{110\ M} = 0.154 M[/tex]
[OH] = 0.154 M
pOH = -log 0.154
= 0.81
pH = 14 – 0.81
= 13.19
pH of the resulting solution is 13.19 .
pH =3.19
The relation between concentration of H+ and OH- ions:
[tex]pH + pOH = 14\\\\pOH = 14 - pH\\\\pOH= 14 - 13.51\\\\pOH= 0.49[/tex]
Concentration of [OH]:
[tex][OH]=10^{-pOH}\\\ [OH]=10^{0.49}=0.323M[/tex]
On adding water to the solution, concentration of the solution gets changed.
[tex]M_1V_1=M_2V_2[/tex]
Initial volume, V1= 100 mL
Final volume, V2 = 100 + 10 = 110 mL
[tex]0.323 M *100 mL = M_2 * 110 mL\\\\M_2=\frac{0.323 M *100 mL}{110MmL} \\\\M_2=0.154M[/tex]
Therefore,
[tex][OH]=0.154M\\\\pOH = -log 0.154 \\\\pOH= 0.81\\\\pH = 14 - 0.81\\\\pH= 13.19[/tex]
Thus, the pH of the resulting solution is 13.19 .
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