Question

In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 1.1 MJ, and the work done on the system is 13.2 kcal. Calculate ΔE (in kJ). Be sure to include the correct sign (+/-). Enter to 0 decimal places.

Answer 1

The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes, distinguishing two kinds of transfer of energy, as heat and as thermodynamic

The formula used for the calculation is as follows:-

$E =q+w$

The value of q and w is given in the question, after applying the equation.

$E =q+w$

After converting, the value of W into joules is:-

$w= 13.2kcal\ = 55.26kj$

Then the value of E is

$E =q+w$

$E= 1100+55.2= 1155.2kj$

Hence, the correction energy is 1155.2j

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