Question

Terrence and Lee were selling magazines for a charity. In the first week, Terrance sold 30% more than Lee. In the second week, Terrance sold 12 magazines, but Lee did not sell any. If Terrance sold 50% more than Lee by the end of the second week, how many magazines did Lee sell? Choose any model to solve the problem. Show your work to justify your answer.

Answer 1

Answer:

Lee sold 60 magazines

Step-by-step explanation:

1st week:

Lee sold = x magazines

Terrence sold $=x+0.3x=1.3x$ magazines (30% more)

2nd week:

Lee sold = 0 magazines

Terrence sold = 12 magazines

Total:

Lee sold = x + 0 = x magazines

Terrence sold = 1.3x + 12 magazines

If Terrance sold 50% more than Lee by the end of the second week, then

x - 100%

1.3x + 12 - 150% (50% more), then

$\dfrac{x}{1.3x+12}=\dfrac{100}{150}\\ \\150x=100(1.3x+12)\\ \\150x=130x+1,200\\ \\150x-130x=1,200\\ \\20x=1,200\\ \\x=60$

Hence, Lee sold 60 magazines