Answer:
The variance of given data is approximately 1.09
Step-by-step explanation:
We are given the following data:
3.5, 1.6, 2.4, 3.7, 4.1, 3.9, 1.0, 3.6, 4.2, 3.4, 3.7, 2.2
Formula:
[tex]\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}[/tex]
where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{37.3}{12} =3.108[/tex]
Sum of squares of differences = 12.029
[tex]\sigma^2 =\dfrac{12.029}{11} = 1.0024 \approx 1.09[/tex]
Thus, the variance of given data is approximately 1.09