Question

How much heat energy, in kilojoules, is required to convert 46.0 gg of ice at −−18.0 ∘C∘C to water at 25.0 ∘C∘C ?

Answer 1

Answer:

1. Energy for 18 to 0 * C

Q = M * Cs * T

(46)(2.09)(18) = 1.73 kj

2. Fusion Energy

Q = M * Change in Fusion      Enthalpy of Fusion Given = 334 J

(46)(334 j) = 15.36 KJ

3. Energy for 0 to 25 * C

(46)(4.18)(25) = 4.807 kj

4. Add all of it up

1.73 + 15.36 + 4.807 = 21.89 kj

Is the answer 21.89 KJ