Question

For the reaction above, when [A] = Km and the enzyme concentration is 3 x 10-8 M (3 x 10-2mM), the velocity of the reaction is 15 µM per min. At saturating [A], each molecule of enzyme can catalyze how many reactions in one minute?

Answer 1

In one minute, each enzyme molecule catalyses $450 \ \frac{\mu \ M^2}{min}$ processes.

Given:

$A= km\\\\\varepsilon_0 =3\times 10^{-8} \ M= 0.03\ mM= 30 \mu M\\\\V_0= V_{max}=V= 15 \frac{\mu M}{min}\\\\s >> km$

To find:

$K_{cat}=?$

Solution:

Using formula:

$\to V_{max}= k_{cat} [\varepsilon_0 ]$

putting the value in the above-given formula:

$\to \frac{15\mu M}{min}=\frac{k_{cat}}{[\varepsilon_0]}\\\\\to \frac{15\mu M}{min}=\frac{k_{cat}}{30\mu M}\\\\\to K_{cat}= 15 \times 30 \ \frac{\mu \ M^2}{min}$

          $= 450 \ \frac{\mu \ M^2}{min}$

Therefore, the final answer is "$450 \ \frac{\mu \ M^2}{min}$".

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