Answer:
%age Yield = 22.72 %
Explanation:
The balance chemical equation is as follow;
2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O
Step 1: Calculate Moles of CaO, NH₄Cl and NH₃;
CaO:
Moles = Mass / M.Mass
Moles = 112 g / 56.07 g/mol
Moles = 1.99 moles of CaO
NH₄Cl:
Moles = Mass / M.Mass
Moles = 224 g / 53.49 g/mol
Moles = 4.18 moles of NH₄Cl
NH₃:
Moles = Mass / M.Mass
Moles = 16.3 g / 17.03 g/mol
Moles = 0.95 moles of NH₃
Step 2: Calculate Limiting reagent as:
According to equation.
2 moles of NH₄Cl reacts with = 1 mole of CaO
So,
4.18 moles of NH₄Cl will react with = X moles of CaO
Solving for X,
X = 4.18 mol × 1 mol / 2 mol
X = 2.09 mol of CaO
This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.
Step 3: Calculate Theoretical Yield of NH₃ as;
According to equation.
2 moles of NH₄Cl produced = 2 moles of NH₃
So,
4.18 moles of NH₄Cl will produce = X moles of NH₃
Solving for X,
X = 4.18 mol × 2 mol / 2 mol
X = 4.18 mol of NH₃
Step 4: Calculate Percentage Yield as;
%age Yield = Actual Yield / Theoretical Yield × 100
%age Yield = 0.95 mol / 4.18 × 100
%age Yield = 22.72 %
