Respuesta :
Answer:
[tex]V(x) = 4x^3-42x^2 +108x[/tex]
Step-by-step explanation:
We are given the following in the question:
Width of sheet = 9 inches
Length of sheet = 12 inches
A square of length x inches is cut from each corner of the sheet to form a box.
Thus, the dimension of the box formed is:
Height = x inches
Width =
[tex]9 - x-x = (9-2x)\text{ inches}[/tex]
Length =
[tex]12 - x-x = (12-2x)\text{ inches}[/tex]
Volume of box formed =
[tex]\text{Length}\times \text{Width}\times \text{Height}[/tex]
Putting values, we get,
[tex]V(x) = (12-2x)(9-2x)x\\V(x) = (12-2x)(9x-2x^2)\\V(x) = 108x-24x^2-18x^2+4x^3\\V(x) = 4x^3-42x^2 +108x[/tex]
is the required expression of volume of box in terms of x.
The volume of a box is the amount of space in it.
The expression that represents volume is: [tex]\mathbf{V = (12 -2x) (9 - 2x)x}[/tex]
The dimension of the cardboard is given as:
[tex]\mathbf{Length = 12}[/tex]
[tex]\mathbf{Width = 9}[/tex]
Assume the cut-out is x.
So, the dimension of the box is:
[tex]\mathbf{Length =12-2x}[/tex]
[tex]\mathbf{Width =9 - 2x}[/tex]
[tex]\mathbf{Height = x}[/tex]
The volume of the box is:
[tex]\mathbf{V = (12 -2x) (9 - 2x)x}[/tex]
Hence, the expression that represents volume is:
[tex]\mathbf{V = (12 -2x) (9 - 2x)x}[/tex]
Read more about volumes at:
https://brainly.com/question/13529955