Question

A(n) 5.77 g bullet is fired into a(n) 2.32 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8 m/s 2 . If the pendulum rises a vertical distance of 7.15 cm, calculate the initial speed of the bullet.

Answer 1

Answer:

23. 77 m/s.

Explanation:

KE = ½mV²

Where,

m = mass in kg

V = velocity in m/s

PE = mgh

g = acceleration of gravity

= 9.8 m/s²

KE of bullet is transferred to PE of pendulum plus bullet

½mV² = mgh

½(0.00577)V² = (0.00577 + 2.32) * (9.8) * (0.0715)

Therefore,

V^2 = 564.88

V = 23.77 m/s