Question

A 3 µC charge is immersed in a 500 N/C uniform electric field (source unknown). How much electric force does this charge experience?

Answer 1

To develop this problem we will apply the concepts related to the Force as the product between the charge and the electric field. That is to say that mathematically it could be described as,

$F = q E$

Here,

q = Charge

E = Electric Field

Our values are given as,

$q = 3 \mu C = 3*10^{-6} C$

$E = 500 N/C$

Replacing,

$F = (3*10^{-6})(500)$

$F = 1.5* 10^{-3} N$

Therefore the electric force is $1.5*10^{-3}N$

Answer 2

Answer:

1.5 x 10⁻³ N or 1.5 mN

Explanation:

The force (F) experienced by an electric charge (Q) in a uniform electric field (E) is given by;

F = Q x E         --------------------------(i)

Where;

Q = 3μ C = 3 x 10⁻⁶C

E = 500N/C

Therefore, substitute these values into equation (i) as follows;

F = 3 x 10⁻⁶ x 500

F = 1.5 x 10⁻³ N or 1.5 mN

The electric force that the charge experiences is 1.5 x 10⁻³ N or 1.5 mN