Question

Terrence and Lee were selling magazines for a charity. In the first week, Terrance sold 30% more than Lee. In the second week, Terrance sold 12 magazines, but Lee did not sell any. If Terrance sold 50% more than Lee by the end of the second week, how many magazines did Lee sell?

Choose any model to solve the problem. Show your work to justify your answer.

Answer 1

Lee sold 60 magazine

Step-by-step explanation:

Terrence and Lee were selling magazines for a charity

• In the first week, Terrance sold 30% more than Lee
• In the second week, Terrance sold 12 magazines, but Lee did not sell any
• Terrance sold 50% more than Lee by the end of the second week

We need to find how many magazines Lee sold

Assume that Lee sold x magazines

∵ Terrance sold 30% more than Lee in the first week

∵ Lee sold x magazines in the first week

- Find 30% of x and add it to x to find how many magazines

  Terrance sold

∵ Terrance sold = 30% × x + x

∴ Terrance sold = $\frac{30}{100}$ × x + x = 0.3 x + x

∴ Terrance sold = 1.3 x magazines in the first week

∵ Terrance sold 12 magazines in the second week

- Add 1.3 x to 12 to find the number of magazines that Terrence

  sold in the two weeks

∴ Terrence sold 1.3 x + 12 magazines in the two weeks

∵ Lee did not sell any in the next week

∴ Lee sold x magazines in the two weeks

∵ Terrance sold 50% more than Lee by the end of the 2nd week

- Equate 1.3 x + 12 by the sum of x and 50% of x

∴ 1.3 x + 12 = 50% × x + x

∵ 50% × x = $\frac{50}{100}$ × x = 0.5 x

∴ 1.3 x + 12 = 0.5 x + x

- Add the like terms in the right hand side

∴ 1.3 x + 12 = 1.5 x

- Subtract 1.3 x from both sides

∴ 12 = 0.2 x

- Divide both sides by 0.2

∴ 60 = x

Lee sold 60 magazine

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