Answer:
B. 1 852 000
Step-by-step explanation:
Population of the country on Jan 1, 2000 = P
r = 2%
total duration = 4 years, : 2000, 2001, 2002, 2003
If we take the compounding of the rate of growth :
2, 000, 000 = P (1 + 2/100)^4 = P (1.02)^4
P = 1, 847,691
If we take the growth of the population similar to simple interest of money deposits, then :
2, 000, 000 = P + P * 2/100 * 4
P = 2, 000, 000 / 1.08 = 1, 851, 852
In this case the answer is B
Answer:
A. 1 846 000
Step-by-step explanation:
A population of size P increasing at the rate of 2% may be modelled as follows
P = P0 e0.02 t , where t is the number of years after t = 0 and P0 is the population at t = 0.
Let t = 0 corresponds to January 1, 2000 and therefore t = 4 corresponds to December 31. But P is 2,000,000 when t = 4. Hence
2,000,000 = P0 e0.02*4
Solve the above for P0
P0 = 2,000,000 / e0.02*4 = 1 846 000 (rounded to the nearest thousand)
P0 is the population at t = 0 or on January 1, 2000.
A. is the correct answer
Hope this helped :)
