Answer : The volume of chloramphenicol stock solution needed is, 0.4 mL
Explanation :
First we have to calculate the mass of chloramphenicol.
As, the mass of chloramphenicol in 1 mL of solution = [tex]25\mu g=25\times 10^{-6}g[/tex]
So, the mass of chloramphenicol in 400 mL of solution = [tex]\frac{400mL}{1mL}\times 25\times 10^{-6}g=0.01g[/tex]
Thus, the mass of chloramphenicol is, 0.01 g
Now we have to calculate the volume of chloramphenicol stock solution needed.
Concentration of chloramphenicol = [tex]25mg/mL=25\times 10^{-3}g/mL[/tex]
As, [tex]25\times 10^{-3}g[/tex] of chloramphenicol needed 1 mL volume of chloramphenicol stock solution
So, [tex]0.01g[/tex] of chloramphenicol needed [tex]\frac{0.01g}{25\times 10^{-3}g}\times 1mL=0.4mL[/tex] volume of chloramphenicol stock solution
Thus, the volume of chloramphenicol stock solution needed is, 0.4 mL