How much of a 25mg/ml chloramphenicol stock solution do we need to make 400ml of growth media that has final 25ug/ml concentration of chloramphenicol?

Respuesta :

Answer : The volume of chloramphenicol stock solution needed is, 0.4 mL

Explanation :

First we have to calculate the mass of chloramphenicol.

As, the mass of chloramphenicol in 1 mL of solution = [tex]25\mu g=25\times 10^{-6}g[/tex]

So, the mass of chloramphenicol in 400 mL of solution = [tex]\frac{400mL}{1mL}\times 25\times 10^{-6}g=0.01g[/tex]

Thus, the mass of chloramphenicol is, 0.01 g

Now we have to calculate the volume of chloramphenicol stock solution needed.

Concentration of chloramphenicol = [tex]25mg/mL=25\times 10^{-3}g/mL[/tex]

As, [tex]25\times 10^{-3}g[/tex] of chloramphenicol needed 1 mL volume of chloramphenicol stock solution

So, [tex]0.01g[/tex] of chloramphenicol needed [tex]\frac{0.01g}{25\times 10^{-3}g}\times 1mL=0.4mL[/tex] volume of chloramphenicol stock solution

Thus, the volume of chloramphenicol stock solution needed is, 0.4 mL

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