Respuesta :
Answer:
Dawn has 32 pens.
Step-by-step explanation:
- Let No. of pens Alice has = A
- Let No. of pens Maurice has = M
- Let no of pens Paul has = P
- Let no. of pens Suzy has = S
- Let no of pens Dawn has = D
Given :
- A = 7M
- P = 2/3 (A + S)
- D = P + 12
- S = 1/2 M
- If S = 2 {Given}
- M = 4 [∵ S = 1/2 M → M = 2S = 2X(2) ]
- A = 28 [ ∵ A = 7M → A = 7 x 4 ]
- P = 20 [∵ P = 2/3 (A+S) → P = 2/3 (28 + 2) = 2/3 (30) ]
- D = 32 [ ∵ D = P + 12 → D = 20 + 12 ]
Dawn has 32 pens which is a dozen more pens than Paul.
Let x represent the amount of pen that Alice has, y that of Maurice, z that of Paul, a that of Suzy
x = 7y
z = 2(a + x)/3
a = y/2
a = 2
a = y/2
2 = y/2
y = 4
x = 7y = 7(4) = 28
z = 2(a + x)/3 = 2(2 + 28)/3 = 20
The amount of pen Dawn has = 12 + z = 12 + 20 = 32
Therefore Dawn has 32 pens
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