Answer:
The 2003 scores have a higher coefficient of variation, so they are more dispersed
Step-by-step explanation:
We have to find the coefficient of variation(CV) for both these tests.
[tex]CV = \frac{\sigma}{\mu}[/tex]
In which [tex]\mu[/tex] is the mean and [tex]\sigma[/tex] is the standard deviation.
Whoever has the higher CV has the higher variation, that is, is more dispersed.
2003
[tex]\mu = 500, \sigma = 80[/tex]
[tex]CV = \frac{\sigma}{\mu} = \frac{80}{500} = 0.16[/tex]
2004
[tex]\mu = 560, \sigma = 84[/tex]
[tex]CV = \frac{\sigma}{\mu} = \frac{84}{560} = 0.15[/tex]
The 2003 scores have a higher coefficient of variation, so they are more dispersed.