Question

Of the 44 students in a class, 38 are taking the class because it is a major requirement, and the other 6 are taking it as an elective. If two students are selected at random from this class, what is the probability that the first student is taking the class as an elective and the second is taking it because it is a major requirement?

Answer 1

Answer:

The probability that of the 2 students selected 1st is taking the class for an elective and 2nd for major is 0.121.

Step-by-step explanation:

The number of students taking the class because it is a major requirement is, n (M) = 38.

The number of students taking the class because it as an elective is, n (E) = 6.

The total number of students is, N = 44.

Two students are selected at random.

Assume that the selection is without replacement.

Compute the  probability that the 1st student selected is taking the class as an elective and the 2nd is taking it because it is a major requirement as follows:

P (1st Elective ∩ 2nd Major) = P (1st Elective) × P (2nd Major)

                                              $=\frac{6}{44}\times \frac{38}{43}\\ =0.120507\\\approx0.121$

Thus, the probability that of the 2 students selected 1st is taking the class for an elective and 2nd for major is 0.121.