Question

What is the maximum number of 7.00 μF capacitors that can be connected in parallel with a 3.00 V battery while keeping the total charge stored within the capacitor array under 953 μC ?

Answer 1

Nearly 45 capacitors are required.

Answer:

Explanation:

It is known that voltage flow in any parallel circuit is tend to be constant. And here the circuit is made up of paralleled arranged capacitors. A capacitor is the one which generates current for a given voltage in the circuit. So the mathematical representation of capacitance is

C = I/V, here I is the current and V is the voltage.

So if  capacitors are connected in parallel, then the sum of varying current will give the equivalent current in the circuit.

I = I1+I2+....In

So, $C_{p} V_{p}=C_{1} V_{1}+ C_{2} V_{2}+ C_{3} V_{3} +......+C_{n} V_{n}$

Since, in the present case, the capacitance is kept constant for all the capacitors connected in parallel and the voltage is constant in parallel circuit connection, then

I= nCV

n = I/CV=953/(3×7) = 45

So nearly 45 capacitors are required.