Trying to find length and area from this triangle.
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Answer:
24, 204
Step-by-step explanation:
to find the height
we would use the heron formula when all the sides are given
S which is equal to half of the perimeter of the triangle which is (a+b+c)/2.
S = (17+ 25+ 26)/2 = 68/2 = 34
Area = √S(S-A)(S-B)(S-C)
Area= (1/2)bh
we equate it back to the formula Area = √S(S-A)(S-B)(S-C)
it becomes
(1/2)bh = √S(S-A)(S-B)(S-C)
A = IABI= 25
B= IBCIM = 26
C= IACI = 17
b = base = IACI = 17
S = 34
(1/2)bh = √S(S-A)(S-B)(S-C)
(1/2)17h = √34(34-25)(34-26)(34-17)
(17/2)h = √34(9)(8)(17) = √34 x 9 x 8 x 17
(17/2)h = √41616 = 204
17h/2 = 204
17h = 204 x 2 = 408
h = 408/17 = 24 inch
height = h = IBDI = 24 in
Area = (1/2)bh
= (1/2) x 17 x 24
= 12 x 17 = 204 or we use the heron formula just like the above which we get 204 before multiplication by 2.