Question

i have no idea how to do this problem

Answer 1

this is the way to solve it

Answer 2

Answer:

Step-by-step explanation:

(a)

1st triangle: 6sqrt(3)cm/sin90 = EH/sin60

9cm/sin90

EH = 9cm

2nd triangle: 9cm/sin45 = TH/sin90

TH = 12.73cm

3rd triangle: AT^2 = (14cm)^2 - (12.73)^2

AT = 5.82cm

(b)

5.82cm/sin(angle) = 14cm/sin90

5.82cm/14cm = sin(angle)

angle = arcsin(5.82/14)

angle = 24.6

angle CHA is 24.6 + 45 + 90 = 159.6