Question

Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Write your answer as a fraction in its simplest form.

Answer 1

The probability of one head and one tail is 2/3.

Step-by-step explanation:

• The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
• Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities

• Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

Answer 2

Using the concept of probability, it is found that there is a $\frac{2}{3}$ probability of one head and one tail.

A probability is the number of desired outcomes divided by the number of total outcomes.

When two coins are flipped, there are 4 possible outcomes, which are: {HH, HT, TH, TT}.

• Fair coins, hence the outcomes are equally as likely.

Of those outcomes:

• 3 have at least one coin landing on a head, which are HH, HT and TH, hence $T = 3$

• 2 of them, HT and TH, have one head and one tail, hence $D = 2$

Hence, the probability is:

$p = \frac{D}{T} = \frac{2}{3}$

$\frac{2}{3}$ probability of one head and one tail.

A similar problem is given at https://brainly.com/question/15536019