A painter is placing a ladder to reach the third story window, which is 19 feet above the ground and makes an angle with the ground of 80. How far out from the building does the base of the latter need to be positioned? Round your answer to the nearest 10th. The base of the latter needs to be positioned__ feet out from the building

A painter is placing a ladder to reach the third story window which is 19 feet above the ground and makes an angle with the ground of 80 How far out from the bu class=

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Answer:

The answer to your question is 3.35 ft

Step-by-step explanation:

Data

height = 19 ft

angle = 80°

Process

1.- It is formed a right triangle so use a trigonometric function that relates the opposite side and the adjacent side. This trigonometric function is tangent.

               tan Ф = Opposite side/adjacent side

               adjacent side = Opposite side / tan Ф

               adjacent side = 19 / tan 80

               adjacent side = 19 / 5.67

               adjacent side = 3.35 ft

Answer: The base of the latter needs to be positioned 3.6 feet out from the building.

Step-by-step explanation:

The ladder forms a right angle triangle with the building and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the where the top of the ladder touches the window to the base of the building represents the opposite side of the right angle triangle.

The distance from the bottom of the ladder to the base of the building represents the adjacent side of the right angle triangle.

To determine distance,h from the bottom of the ladder to the base of the building, we would apply

the tangent trigonometric ratio.

Tan θ = opposite side/adjacent.

Tan 80 = 19/h

h = 19/Tan 80 = 19/5.6713

h = 3.6 feet

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