Answer:
[tex]x=x+12[/tex]
Step-by-step explanation:
Given equation :
[tex]3(x-2)+x=2(2x-8)+22[/tex]
To find the value x in such equation, take the terms of 'x' to one side and constants to the other side.
[tex]3x-6+x=4x-16+22[/tex]
[tex]x= 4x+6+6-3x\\x=x+12[/tex]
In the equation the variable x is getting cancelled on solving in terms of constants. To sustain the value of 'x' we are taking
[tex]x=x+12[/tex]