Answer:
First figure: [tex]954cm^3[/tex]
Second figure: [tex]1,508yd^3[/tex]
Third figure:
- Height= q
- Side length = r
Fourth figure: [tex]726cm^3[/tex]
Explanation:
A. First figure:
1. Formula:
[tex]\text{Volume of a cylinder}=\pi \times radius^2\times length[/tex]
2. Data:
3. Substitute in the formula and compute:
[tex]Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3[/tex]
B. Second figure
1. Formula:
[tex]\text{Volume of a leaned cylinder}=\pi \times radius^2\times height[/tex]
2. Data:
3. Substitute and compute:
[tex]Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3[/tex]
C) Third figure
a) The height is the segment that goes vertically upward from the center of the base to the apex of the pyramid, i.e. q .
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e. r .
When the base of the pyramid is a square the four edges of the base have the same side length.
D) Fourth figure
1. Formula
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).
[tex]Volume=(1/3)B\times H[/tex]
2. Data:
- side length of the base: 11 cm
3. Calculations
a) Calculate the area of the base.
The base is a square of side length equal to 11 cm:
[tex]\text{Area of the base}=B=(11cm)^2=121cm^2[/tex]
b) Volume of the pyramid:
[tex]Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3[/tex]
