Question

Algebra problem!!! Please help me!!!

Answer 1

Good morning Brainiac

x+y = 13

1/2 x +y = 10

We gonna solve x+y=13 for x

So let's start by adding -y to both sides

x+y -y = 13-y

x= -y +13

Now substitute -y+13 for x in 1/2 x +y=10

1/2 x +y = 10

1/2 (-y+13)+y=10

1/2 y + 13/2 = 10

Now add -13/2 to both sides

1/2 y+13/2 -13/2 = 10- 13/2

1/2 y = 7/2

Now eliminate the common denominator which is 2

y = 7

Now we have the value for y, so lets find the value for x by substitute 7 for y in x= -y+13

x= -y+13

x= -7 + 13

x= 6

Answer : (6,7)

The answer is B

I hope that's help and if you have questions please let me know :)

Good luck

Answer 2

$\left \{ {{y=13} \atop {x=10}} \right. \sqrt[n]{x} \lim_{n \to \infty} a_n${ x+y=13

1/2 x y = 10

A. (5,8)

B. (6,7)

C. (8,5)

D. (7,6)

look at the facts don't know but I think it is C. (8,5)