Question

Write a linear equation in the form y = mx + b that has a slope of 4 and passes through the point (–2, –5)

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A)
y = 4x – 2

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B)
y = 4x – 5

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C)
y = 4x – 13

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D)
y = 4x + 3

Answer 1

Answer:

(D). $y =4x + 3$

Step-by-step explanation:

Given:

Slope of the line (m) = 4

A point on the line is, $(x_1,y_1)=(-2,-5)$

Now, the point-slope form of a line is given as:

$y-y_1=m(x-x_1)$

Plug in the given values and simplify the equation in the form $y=mx+b$.

This gives,

$y-(-5)=4(x-(-2))\\\\y+5=4(x+2)\\\\y+5=4x+8...(Distributive\ property)\\\\y=4x+8-5...(Subtraction\ property\ of\ equality)\\\\y=4x+3$

Therefore, the correct option is (D). y =4x + 3