Question

6. Can someone explain how to solve this?

Answer 1

Answer:

$( \frac{\pi}{6} - \frac{ \sqrt{3} }{4} )f {t}^{2}$

Step-by-step explanation:

$area \: of \: sector \: rst \: = \frac{60}{360} \times \pi(1) {}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi}{6}$

$area \: of \: triangle \: rst \: = \: \frac{1}{2} (1)(1) \\ \sin(60) \\ = \frac{ \sqrt{3} }{4}$

$area \: of \: shaded \: region \\ = \frac{\pi}{6} - \frac{ \sqrt{3} }{4 }$